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avoid talking about inverses
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@@ -607,8 +607,9 @@ pub fn mask(self, mask: usize) -> *const T {
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/// Calculates the distance between two pointers. The returned value is in
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/// units of T: the distance in bytes divided by `mem::size_of::<T>()`.
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///
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/// This function is the inverse of [`offset`]: it is valid to call and will return
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/// `n` if and only if `origin.offset(n)` is valid to call and will return `self`.
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/// This is equivalent to `(self as isize - origin as isize) / (mem::size_of::<T>() as isize)`,
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/// except that it has a lot more opportunities for UB, in exchange for the compiler
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/// better understanding what you are doing.
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///
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/// [`offset`]: #method.offset
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///
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@@ -617,7 +618,7 @@ pub fn mask(self, mask: usize) -> *const T {
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/// If any of the following conditions are violated, the result is Undefined
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/// Behavior:
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///
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/// * Both the starting and other pointer must be either in bounds or one
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/// * Both `self` and `origin` must be either in bounds or one
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/// byte past the end of the same [allocated object].
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///
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/// * Both pointers must be *derived from* a pointer to the same object.
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@@ -651,8 +652,9 @@ pub fn mask(self, mask: usize) -> *const T {
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/// needed for `const`-compatibility: the distance between pointers into *different* allocated
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/// objects is not known at compile-time. However, the requirement also exists at
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/// runtime and may be exploited by optimizations. If you wish to compute the difference between
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/// pointers that are not guaranteed to be from the same allocation, use `(self as
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/// usize).sub(origin as usize) / mem::size_of::<T>()`.
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/// pointers that are not guaranteed to be from the same allocation, use `(self as isize -
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/// origin as isize) / mem::size_of::<T>()`.
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// FIXME: recommend `addr()` instead of `as usize` once that is stable.
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///
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/// [`add`]: #method.add
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/// [allocated object]: crate::ptr#allocated-object
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@@ -781,8 +781,9 @@ pub const fn guaranteed_ne(self, other: *mut T) -> Option<bool>
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/// Calculates the distance between two pointers. The returned value is in
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/// units of T: the distance in bytes divided by `mem::size_of::<T>()`.
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///
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/// This function is the inverse of [`offset`]: it is valid to call and will return
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/// `n` if and only if `origin.offset(n)` is valid to call and will return `self`.
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/// This is equivalent to `(self as isize - origin as isize) / (mem::size_of::<T>() as isize)`,
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/// except that it has a lot more opportunities for UB, in exchange for the compiler
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/// better understanding what you are doing.
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///
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/// [`offset`]: pointer#method.offset-1
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///
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@@ -791,7 +792,7 @@ pub const fn guaranteed_ne(self, other: *mut T) -> Option<bool>
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/// If any of the following conditions are violated, the result is Undefined
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/// Behavior:
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///
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/// * Both the starting and other pointer must be either in bounds or one
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/// * Both `self` and `origin` must be either in bounds or one
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/// byte past the end of the same [allocated object].
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///
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/// * Both pointers must be *derived from* a pointer to the same object.
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@@ -825,8 +826,9 @@ pub const fn guaranteed_ne(self, other: *mut T) -> Option<bool>
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/// needed for `const`-compatibility: the distance between pointers into *different* allocated
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/// objects is not known at compile-time. However, the requirement also exists at
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/// runtime and may be exploited by optimizations. If you wish to compute the difference between
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/// pointers that are not guaranteed to be from the same allocation, use `(self as
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/// usize).sub(origin as usize) / mem::size_of::<T>()`.
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/// pointers that are not guaranteed to be from the same allocation, use `(self as isize -
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/// origin as isize) / mem::size_of::<T>()`.
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// FIXME: recommend `addr()` instead of `as usize` once that is stable.
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///
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/// [`add`]: #method.add
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/// [allocated object]: crate::ptr#allocated-object
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